Calculate the final temperature of 244 of water initially at 35 upon absorption of 20 of heat
You need units for these numbers; only mind readers can help you out without them.
To calculate the final temperature of water after absorbing a certain amount of heat, we can use the equation:
q = m * c * ΔT
Where:
- q is the amount of heat absorbed or released
- m is the mass of the substance
- c is the specific heat capacity of the substance
- ΔT is the change in temperature
In this case, we have:
- q = 20 J (given)
- m = 244 g (given)
- c = 4.18 J/g°C (specific heat capacity of water)
- ΔT = final temperature - initial temperature
Let's rearrange the equation to solve for ΔT:
ΔT = q / (m * c)
ΔT = 20 J / (244 g * 4.18 J/g°C)
ΔT ≈ 0.019°C
Now we can find the final temperature by adding the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 35°C + 0.019°C
Final temperature ≈ 35.019°C
Therefore, the final temperature of the water after absorbing 20 J of heat would be approximately 35.019°C.