A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 6.10 m/s?
V^2 = Vo^2 + 2a*d
d = (V^2-Vo^2)/2a
d = (6.10^2-0)/2.4
To find the distance the boy would travel, we can use the equation of motion:
v^2 = u^2 + 2a * s
Where:
v = final velocity (6.10 m/s)
u = initial velocity (0 m/s)
a = acceleration (1.20 m/s^2)
s = distance
We need to rearrange the equation to solve for s:
s = (v^2 - u^2) / (2a)
Now we can substitute the given values into the equation:
s = (6.10^2 - 0^2) / (2 * 1.20)
Simplifying the equation:
s = (37.21) / (2.40)
s ≈ 15.50 meters
Therefore, the boy would reach a speed of 6.10 m/s in approximately 15.50 meters.