physics

A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 6.10 m/s?

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asked by paige
  1. V^2 = Vo^2 + 2a*d
    d = (V^2-Vo^2)/2a
    d = (6.10^2-0)/2.4

    posted by Henry

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