how would you prepare a 550ml of 0.350 normal calcium chloride solution
To prepare a 550ml of 0.350 normal calcium chloride solution, you will need to know the molar mass of calcium chloride and have the required amounts of calcium chloride and water.
Here's a step-by-step explanation on how to prepare the solution:
1. Determine the molar mass of calcium chloride (CaCl2). It consists of one calcium atom (Ca) with a molar mass of 40.08 g/mol and two chlorine atoms (Cl) with a molar mass of 35.45 g/mol each. So, the molar mass of calcium chloride is:
40.08 g/mol (Ca) + 2 * 35.45 g/mol (Cl) = 110.98 g/mol
2. Calculate the number of moles of calcium chloride required. Since you want a 0.350 normal solution, this means you need 0.350 moles of calcium chloride per liter (L) of solution. Since you want 550ml (0.55L), the number of moles can be calculated as follows:
Moles of calcium chloride = 0.350 moles/L * 0.55 L = 0.1925 moles of CaCl2
3. Calculate the mass of calcium chloride needed. Using the molar mass of calcium chloride calculated earlier, you can determine the mass required in grams:
Mass of calcium chloride = Moles of calcium chloride * Molar mass of calcium chloride
Mass of calcium chloride = 0.1925 moles * 110.98 g/mol = 21.26 grams
4. Weigh out 21.26 grams of calcium chloride using a balance.
5. Transfer the weighed calcium chloride into a container that can hold at least 550ml of solution.
6. Add distilled water to make up the final volume. Pouring slowly, add water while stirring until you reach the 550ml mark.
7. Stir the solution gently until the calcium chloride dissolves completely.
That's it! You have prepared a 550ml of 0.350 normal calcium chloride solution.