What acceleration will cause a bus to travel a distance of 200 meters in 10 sec if it starts from rest
Wow, a "dragster bus"
v = at + c , a is the acceleration, v is the velocity and c is a constan
when t = 0, v = 0
so c = 0 and v = at
s = (1/2)at^2 + k , were s is distance and k is a constant
when t = 0 , s=0 and thus k = 0
we have s = (1/2)at^2
(our physics tutors probably would have started here)
when t = 10 , s = 200
200 = (1/2)a(100)
400 = 100a
a = 4
the bus would have to accelerate at 4 m/sec^2
To calculate the acceleration, we can use the equation of motion:
distance = initial velocity * time + 0.5 * acceleration * time^2
The problem states that the bus starts from rest, so the initial velocity is 0 m/s. Therefore, the equation simplifies to:
distance = 0.5 * acceleration * time^2
Substituting the given values into the equation:
200 = 0.5 * acceleration * (10^2)
Simplifying further:
200 = 0.5 * 100 * acceleration
Dividing both sides of the equation by 50:
4 = acceleration
So, the acceleration that would cause the bus to travel a distance of 200 meters in 10 seconds, starting from rest, is 4 m/s^2.