A 75.0kg bobsled is pushed along a horizontal surface by two athletes. After the bobsled is pushed a distance of 4.5m starting from the rest, its speed is 6.0m/s. Find the magnitude of the net force on the bobsled.
Fd=0.5mv^2
F(4.5)=0.5(75)(6.0)^2
F=0.5(75)(6.0)^2/4.5
F=300N
Wnet = 1/2mv^2 (Final) - 1/2mv^2 (Initial)
Initial = 0 because the sled started from rest, so we first need to find the final.
KE = 1/2mv^2
m = 75kg
v = 6m/s
KE = 1/2 (75)(36)^2 = 1350j
1350j is our energy, to find force we use
E = Fd so F= E/d
d = 4.5m
F= 1350/4.5 = 300N
300N is our final force, and we already know our initial force is 0
So, using Wnet = 1/2mv^2 (Final) - 1/2mv^2 (Initial) we can figure out our net force
Wnet = 300N - 0N
Wnet = 300N
Wnet = 1/2mv^2 (Final) - 1/2mv^2 (Initial)
Initial = 0 because the sled started from rest, so we first need to find the final.
KE = 1/2mv^2
m = 75kg
v = 6m/s
KE = 1/2 (75)(36)^2 = 1350j
1350j is our energy, to find force we use
E = Fd so F= E/d
d = 4.5m
F= 1350/4.5 = 300N
300N is our final force, and we already know our initial force is 0
So, using Wnet = 1/2mv^2 (Final) - 1/2mv^2 (Initial) we can figure out our net force
Wnet = 300N - 0N
Wnet = 300N
Well, if you're looking for the net force on the bobsled, we can use Newton's second law, which states that the net force is equal to the mass of an object multiplied by its acceleration.
Now, the bobsled started from rest and reaches a final velocity of 6.0m/s after being pushed a distance of 4.5m. We can use these values to find the acceleration.
To find the acceleration, we can use one of Newton's kinematic equations:
v^2 = u^2 + 2as
where:
v = final velocity = 6.0m/s (given)
u = initial velocity = 0 (since it started from rest)
a = acceleration
s = displacement = 4.5m (given)
Rearranging the equation, we can solve for the acceleration:
a = (v^2 - u^2)/(2s)
a = (6.0^2 - 0)/(2 * 4.5)
a = 72/9
a = 8.0m/s^2
Now that we know the acceleration, we can use Newton's second law to find the net force:
F = ma
F = (75.0kg)(8.0m/s^2)
F = 600N
So, the magnitude of the net force on the bobsled is 600 Newtons. However, if I were a mathematician, I'd probably say that the force is "bobsled-aful."
To find the magnitude of the net force on the bobsled, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).
First, let's calculate the acceleration of the bobsled using the equation for uniform acceleration:
v^2 = u^2 + 2as
Where:
v = final velocity = 6.0 m/s
u = initial velocity = 0 m/s (starting from rest)
a = acceleration (unknown)
s = displacement = 4.5 m
Rearranging the equation to solve for a, we get:
a = (v^2 - u^2)/(2s)
Substituting in the given values, we have:
a = (6.0^2 - 0^2) / (2 * 4.5)
= 36.0 / 9.0
= 4.0 m/s^2
Now, we can use Newton's second law to find the net force acting on the bobsled:
F = m * a
Substituting the given mass (m) of the bobsled, we have:
F = 75.0 kg * 4.0 m/s^2
= 300 N
Therefore, the magnitude of the net force on the bobsled is 300 Newtons.
a= v²/2s
F=ma
Given:
m=75kg
d=4.5m
v=6.00m/s
angle=180
Required:
F=?
Formrula:
W=change of KE
Same as:
-0.5mv^2=Fdcos()
Solve for F
F=-0.5mv^2/dcos()
F=-0.5(75kg)(6.00m/s)^2/(4.5)(cos 180)
F=-225/-4.5
F=50N