balance: H3PO4 + Mg(OH)2 → Mg3(PO4)2 + H2O

This could be the answer, 2 H3PO4 + 3 Mg(OH)2 --> Mg3(PO4)2 + 6 H20

It could be and is.

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To balance the chemical equation H3PO4 + Mg(OH)2 → Mg3(PO4)2 + H2O, we need to make sure that there is an equal number of each type of atom on both sides of the equation.

1. Let's start with the phosphorus (P) atoms. We have 1 atom of P on the left side and 2 atoms of P on the right side. To balance it, we can put a coefficient of 2 in front of H3PO4:

2 H3PO4 + Mg(OH)2 → Mg3(PO4)2 + H2O

2. Now let's balance the hydrogen (H) atoms. We have 6 hydrogen atoms on the left side (3 in H3PO4 and 3 in H2O), and only 2 hydrogen atoms on the right side. To balance it, we can put a coefficient of 3 in front of H2O:

2 H3PO4 + Mg(OH)2 → Mg3(PO4)2 + 3 H2O

3. Finally, let's balance the magnesium (Mg) atoms. We have 1 Mg atom on the left side and 3 Mg atoms on the right side. To balance it, we can put a coefficient of 3 in front of Mg(OH)2:

2 H3PO4 + 3 Mg(OH)2 → Mg3(PO4)2 + 3 H2O

Now the equation is balanced with equal numbers of each type of atom on both sides.