# Calculus

Solve:
The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds.
Find the particle's velocity at t=1 sec.

A) 2/3 m/sec
B) 4/3 m/sec
C) -1/3 m/sec
D) 1/6 m/sec

Thank you!

1. 3
1. Differentiate s(t). The derivative, ds/dt, is the speed as a function of t.

ds/dt = [(1/2)/sqrt(5 +4t)]*4
= 2/sqrt(5+4t)
At t = 1, this equals 2/(sqrt9) = 2/3

posted by drwls

## Similar Questions

1. ### calculus

A particle is moving along the curve below. y = sqrt(x) As the particle passes through the point (4,2), its x-coordinate increases at a rate of 4 cm/s. How fast is the distance from the particle to the origin changing at this
2. ### calulus

a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its x-coordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?
3. ### Calculus: need clarification to where the #'s go

A particle is moving along the curve y= 2 \sqrt{4 x + 4}. As the particle passes through the point (3, 8), its x-coordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to
4. ### Calculus 1

A particle is moving along the curve y= 4 \sqrt{3 x + 1}. As the particle passes through the point (1, 8), its x-coordinate increases at a rate of 2 units per second. Find the rate of change of the distance from the particle to
5. ### Calculus HELP

A particle is moving along the curve y=5 sqrt (2x+6). As the particle passes through the point (5,20 , its x-coordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to the
6. ### Math

A particle is moving along the curve y= 2 \sqrt{4 x + 4}. As the particle passes through the point (3, 8), its x-coordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to
7. ### Calc

A particle is moving along the curve y= 3 \sqrt{3 x + 4}. As the particle passes through the point (4, 12), its x-coordinate increases at a rate of 4 units per second. Find the rate of change of the distance from the particle to
8. ### Calc

A particle is moving along the curve y= 4 sqrt{2 x + 2}. As the particle passes through the point (1, 8), its x-coordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to the
9. ### physics

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.690 g, q = 4.75 µC) is located on the x axis at x = 20.0 cm, moving with a speed of 50.0 m/s in the positive y direction. For
10. ### calculus

the position of a particle moving along a coordinate line is s=√(1+4t) , with s in metres and t in seconds. Find the particle's velocity and acceleration at t=6 sec

More Similar Questions