chemistry

The air within a piston equipped with a cylinder absorbs 570J of heat and expands from an initial volume of 0.12L to a final volume of 0.88L against an external pressure of 1.0 atm. What is the change in internal energy of the air within the piston?

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  1. delta E = w + q
    q=570 J
    V1 = 0.12 L
    V2 = 0.88 L
    delta V = 0.88 L - 0.12 L = 0.76 L
    w = -P x delta V
    w = -1.0 atm x 0.76 L = -0.76 L atm
    You need to convert L atm to J
    -0.76 L atm / 1 L atm x 101.3 J = -76.99 J
    delta E = -76.99 J + 570 J = 493 J

    Mastering Chemistry accepts this answer as Correct

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