calculus

Determine the quadratic function f, whose graph is given. **The graph given is (0,-2) and (3,-11)

The vertex is (3,11) and the y-intercept is -2

So, f(x)=

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1. come on, guy. You should be getting the hang of these by now.

the vertex says
f(x) = a(x-3)^2 + 11
the point (0,-2) says
-2 = 9a+11
a = -13/9

f(x) = -13/9 (x-3)^2 + 11

would have been nicer with a y-intercept of +2.

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