A 10.00 mL volume of sulfuric acid required 23.65 mL of NaOH solution for complete neutralization. What is the molarity of the acid solution?
To find the molarity (M) of the sulfuric acid solution, we can use the concept of stoichiometry and the volume of NaOH solution required for neutralization.
First, let's write the balanced chemical equation for the reaction:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the balanced equation, we can see that one mole of sulfuric acid reacts with two moles of sodium hydroxide.
Since the volume and concentration of NaOH solution are not given, we need to find the number of moles of NaOH using the volume of NaOH solution required for neutralization.
The molarity (M) of a solution is defined as the number of moles of solute divided by the volume of the solution in liters.
Steps to find the molarity of the sulfuric acid solution:
1. Convert the volume of NaOH solution to liters.
Volume of NaOH solution = 23.65 mL = 23.65/1000 = 0.02365 L
2. Determine the number of moles of NaOH using its molarity and volume.
As the molarity of NaOH is not given, this step cannot be completed without additional information.
At this point, we need to know the molarity of the NaOH solution to continue the calculation and find the molarity of the sulfuric acid solution.