# calculus

determine the average value of f(x) over the interval from x=a to x=b, where f(x)=100e^-.5x; a=0, b=4

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1. (1/4) integral from 0 to 4 of 100 e^-.5 x dx

25 int e^-.5x dx

25 (-2)e^-.5x at 4 - at 0

-50 [ e^-2 - e^0]

-50 [ .135 - 1 ]

-50 [ -.864 ]

43.2

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posted by Damon

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