A rectangular wall is 22.7 feet long and 7.5 feet high. If the door in the wall is 2 feet wide and 6.5 feet high, what is the area of the wall excluding the door?
Area of wall:
A = 22.7 * 7.5
Area of door:
A = 6.5 * 2
Subtract the area of the door from the area of the wall.
13
To find the area of the wall excluding the door, we need to calculate the area of the entire wall and then subtract the area of the door.
The area of a rectangle can be found by multiplying its length and width. In this case, the length of the wall is 22.7 feet and the height of the wall is 7.5 feet.
So, the area of the wall is:
Area of wall = length × height
= 22.7 ft × 7.5 ft
Next, we need to calculate the area of the door. The width of the door is 2 feet and the height of the door is 6.5 feet.
So, the area of the door is:
Area of door = width × height
= 2 ft × 6.5 ft
Now, subtracting the area of the door from the area of the wall will give us the area of the wall excluding the door:
Area of wall excluding door = Area of wall - Area of door
Substituting the values we have:
Area of wall excluding door = (22.7 ft × 7.5 ft) - (2 ft × 6.5 ft)
Now we can calculate the area using a calculator or by simplifying the expression:
Area of wall excluding door = 170.25 ft² - 13 ft²
= 157.25 ft²
Therefore, the area of the wall excluding the door is 157.25 square feet.