Physics

The force required to stretch a Hooke’s-law spring varies from 0 N to 70.4 N as we stretch the spring by moving one end 5.35 cm from its unstressed position.
Find the force constant of the spring. Answer in units of N/m

asked by Patrick
  1. F = -k*x

    where F = force, x is displacement

    70.4 = -k*0.0535

    posted by Jennifer

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