chemistry

A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.87 kg m-3. Under these conditions the total surface area of the balloon is 0.87 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.

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  1. anyone got it right?

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    posted by mango
  2. Im struggling with it, at least any hints?

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  3. What is the formula to use

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    posted by chelo
  4. pls. tell

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    posted by C
  5. CHEAT!

    Do NOT help this person. They are trying to cheat in a midterm exam.

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    posted by MIT2
  6. same here, how to insert the data into the formula?

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    posted by Ling
  7. the formula?

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    posted by chelo
  8. Fick’s Law
    M= -D•(Δρ/Δx)•A,
    where
    M = m/t = mass flux [kg/s],
    D= 4.9•10 ⁻⁹ m ²/s is the diffusion coefficient (diffusivity) [m²/s],
    Δρ/Δx is the gradient of density [kg/m⁴],
    A is the area [m²].

    M= - 4.9•10⁻⁹•(0 - 0.35)/3.091•10⁻⁴)•0.88 =
    4.9•10⁻⁹•0.35•0.88/3.091•10⁻⁴=
    =4.88•10⁻⁶ kg/s= 17.58 g/hr

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    posted by Stud
  9. doesnt work for me. the answer is still wrong

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