trigonmetry

find all solutions for
tan^2 theta -4 = 0

i got theta = arctan 2

is that correct? and if it is how would i write it as a solution?

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asked by v
  1. theta = arctan2 or arctan -2
    because tan^2 = 4, so tan is +/- 2

    that's as exact as you can get. Just as pi or sqrt(7) is a perfectly valid number, so is arctan(2)

    just be sure to note that since arctan(-2) = pi-arctan(2), the complete solution set is

    k*pi+/-Arctan(2)

    where Arctan(2) is the principal value.

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    posted by Steve

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