# Math

Peter has 1200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area?

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1. It's a square.

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2. So what exactly would the answer be? im confused..

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posted by Jane
3. 1200/4 = 300 yards on each side.

A = 300 * 300

A = ?

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4. Oh i see now! Ok thank you!

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posted by Jane
5. Finding the Absolute Area....

Area of the fence:
A=x*y

Perimeter of the fence
2x+2y=1200

Then, you solve for one variable
2x=1200-2y
x=600-y <-- plug this back into the Area function and you will get

A=(600-y)y
A=600y-y^2

And I believe you can set that equal to zero
-y^2+600y=0

Then you use the quadratic formula
b=600
a=-1
so y= -600/(2)*(-1)
y=300

That'll give you one side, then plug it back to perimeter equation to get x. Hope this is right!

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posted by A.
6. You're welcome.

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