can i use factoring to simplify this trig identity?
the problem is sinx + cotx * cosx i know the answer is cscx and i know how to get it but i want to know if i can do factoring to get it bc i tried to but it wont give me the answer .
this is the step i went through:
1) sinx + cotx * cosx turns into sinx +(cosx/sinx)*cosx
2) i try to factor out sinx so that i would get sinx(1+ cosx * cosx)
3) that left me with sinx(1+cos^(2) x) that's where i im lost can anyone enlighten me plz

  1. 👍 0
  2. 👎 0
  3. 👁 292
  1. cot = cos/sin, so you have

    sin + cos^2/sin
    = (sin^2+cos^2)/sin
    = 1/sin
    = csc

    1. 👍 0
    2. 👎 0
  2. im well aware of that steve thank you for answering but i really wanted to know was is it at all possible to use factoring to solve this like i have up there

    1. 👍 0
    2. 👎 0
  3. I don't see any way to use factoring. You don't in fact come up with


    because you have that pesky 1/sin under the cos^2.

    If you try to fractor out the sin, you get


    and again you end up with sin^2+cos^2 on top.

    1. 👍 0
    2. 👎 0
  4. We could do some " silly" factoring

    sinx + (cosx/sinx)(cosx)
    = sinx + cos^2 x (sinx)^-1
    = (sinx)^-1 (sin^2 x + cos^2 x)
    = (sinx)^-1
    = 1/sinx
    = cscx

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Trigonometry

    Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)

  2. Calculus

    Prove the identity cscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx

  3. Precalculus

    Rewrite as single trig function: sin(8x)cosx-cos(8x)sinx I know I can simplify sin(8x) into 4sin2xcos2xcos4x, but I'm stuck after that

  4. math;)

    The equation 2sinx+sqrt(3)cotx=sinx is partially solved below. 2sinx+sqrt(3)cotx=sinx sinx(2sinx+sqrt(3)cotx)=sinx(sinx) 2sin^2x+sqrt(3)cosx=sin^2x sin^2x+sqrt(3)cosx=0 Which of the following steps could be included in the

  1. Trigonometry

    verify the identity: 1- (cos^2x)/(1-sinx)= -sinx

  2. trigonometry

    how do i simplify (secx - cosx) / sinx? i tried splitting the numerator up so that i had (secx / sinx) - (cosx / sinx) and then i changed sec x to 1/ cosx so that i had ((1/cosx)/ sinx) - (cos x / sinx) after that i get stuck

  3. Math

    (sinx - cosx)(sinx + cosx) = 2sin^2x -1 I need some tips on trigonometric identities. Why shouldn't I just turn (sinx + cosx) into 1 and would it still have the same identity?

  4. College Algebra

    verify the identity. cotx secx sinx=1

  1. Math 12

    Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do.

  2. Pre-Calculus

    Find a numerical value of one trigonometric function of x if tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1 d)sinx=1/2

  3. Trigonometry Check

    Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] = [cosx-((1)cosx-(0)sinx)sinx]/[cosx-((-1)cosx+(0)sinx)tanx] = [cosx-cosxsinx]/[cosx+cosxtanx] =

  4. Trigonometry.

    ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated

You can view more similar questions or ask a new question.