What is the magnitude of the electric field 0.3 m from a 10-4 C point charge?
E = ke*|Q|/r^2
where ke is Coulomb's constant, Q is the charge, r is the distance from the charge
E = (ke*10^-4)/0.3^2
To find the magnitude of the electric field, we can use Coulomb's law which states that the electric field strength produced by a point charge is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance from the charge.
The formula for calculating the electric field magnitude (E) is:
E = k * (Q / r^2)
Where:
- E is the electric field magnitude
- k is the Coulomb's constant (approximately 9.0 x 10^9 Nm^2/C^2)
- Q is the magnitude of the point charge
- r is the distance from the point charge
In this case, the magnitude of the charge (Q) is given as 10^-4 C, and the distance (r) is given as 0.3 m.
Plugging these values into the formula, we get:
E = (9.0 x 10^9 Nm^2/C^2) * (10^-4 C / (0.3 m)^2)
Simplifying further:
E = (9.0 x 10^9 Nm^2/C^2) * (10^-4 C / 0.09 m^2)
E = (9.0 x 10^5 Nm^2) / (0.09 m^2)
E = 1.0 x 10^7 N/C
Therefore, the magnitude of the electric field 0.3 m from a 10^-4 C point charge is 1.0 x 10^7 N/C.