What volume of 1.75M CaSO3 solution could be prepared from 450g of CaSO3?
To determine the volume of a solution that can be prepared from a given mass of solute, you need to use the molarity and molar mass of the solute. Here's how you can do it step by step:
Step 1: Find the molar mass of CaSO3 (calcium sulfate).
CaSO3 consists of one calcium atom (Ca) with a molar mass of 40.08 g/mol, one sulfur atom (S) with a molar mass of 32.07 g/mol, and three oxygen atoms (O) with a combined molar mass of 3 × 16.00 g/mol.
So, the molar mass of CaSO3 is:
40.08 g/mol + 32.07 g/mol + (3 × 16.00 g/mol) = 120.14 g/mol
Step 2: Calculate the number of moles of CaSO3 in the given mass.
To convert mass to moles, divide the given mass by the molar mass:
450g / 120.14 g/mol = 3.7468 mol
Step 3: Use the molarity formula to find the volume of the solution.
The molarity (M) is defined as the number of moles of solute (CaSO3) dissolved in one liter of solution.
1.75 M CaSO3 means there are 1.75 moles of CaSO3 in one liter of solution.
To find the volume of the solution that can be prepared from the given moles of CaSO3, use the following equation:
Volume (in liters) = Moles of solute / Molarity
Volume = 3.7468 mol / 1.75 mol/L
Step 4: Calculate the volume in liters.
Volume = 2.1408 L
So, the volume of a 1.75 M CaSO3 solution that can be prepared from 450 g of CaSO3 is 2.1408 liters.