algebra

suppose you want to build a rectangular sandbox where the width is 4 ft less than the length and the diagonal is 4 ft longer than the length. what are the dimensions

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asked by carlos
  1. (x+4)^2 = x^2 + (x-4)^2

    x^2 + 8 x + 16 = x^2 + x^2 - 8 x + 16

    x^2 -16 x = 0
    x = 0 or x = 16
    so x = 16
    12, 16, 20

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    posted by Damon
  2. Suppose you want to build a rectangular picture frame where the width is 2 centimeters less than the length and the diagonal is 2 centimeters longer than the length. What are the dimensions of the picture frame?

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  3. ?

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