Reaction:
CaCO3 + 2 HCl -> CaCl2 + CO2 + H2O
Calculate the molarity of hydrochloric acid solution if an initial mass of 4.568g of CaCO3 was reacted with 25.0mL of the acid and 2.678g of CaCO3 remain after the reaction is complete.
g CaCO3 reacted = 4.568 g - 2.678g = ?g CaCO3 used in the titration.
mols CaCO3 = gCaCO3 used/molar mass =?
mols HCl = twice that (from the balanced equation coefficients)
M HCl = mols HCl/L HCl.
1.890CaCO3/1 x 1mole CaCO3/100.09 x2molesHCl/1mole CaCO3 x1/0.025
=1.5
To calculate the molarity of the hydrochloric acid (HCl) solution, we need to know the moles of HCl present in the reaction.
First, let's determine the moles of CaCO3 reacted:
Step 1: Calculate the moles of CaCO3 initially present.
Molar mass of CaCO3 = atomic mass of Ca + 3 × atomic mass of C + 3 × atomic mass of O
= (40.08 g/mol) + 3 × (12.01 g/mol) + 3 × (16.00 g/mol)
= 100.09 g/mol
Moles of CaCO3 initially present = mass of CaCO3 / molar mass of CaCO3
= 4.568 g / 100.09 g/mol
Step 2: Calculate the moles of CaCO3 remaining.
Moles of CaCO3 remaining = mass of CaCO3 remaining / molar mass of CaCO3
= 2.678 g / 100.09 g/mol
Step 3: Calculate the moles of CaCO3 reacted.
Moles of CaCO3 reacted = Moles of CaCO3 initially present - Moles of CaCO3 remaining
Now that we have the moles of CaCO3 reacted, we can determine the moles of HCl reacted:
From the balanced equation:
1 mole of CaCO3 reacts with 2 moles of HCl
Step 4: Calculate the moles of HCl reacted.
Moles of HCl reacted = 2 × Moles of CaCO3 reacted
Finally, we can calculate the molarity of the HCl solution:
Step 5: Calculate the volume in liters of the HCl solution.
Volume of HCl solution = 25.0 mL = 0.0250 L (since 1 L = 1000 mL)
Step 6: Calculate the molarity of HCl.
Molarity (M) = Moles of HCl reacted / Volume of HCl solution in liters
By following these steps and plugging in the calculated values, you should be able to find the molarity of the hydrochloric acid solution.