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Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).

(0 is not the number zero I don't know what its called)

I have to find r first.

r=sqrt x^2+y^2
r=sqrt -5^2+-4^2
r=sqrt 41

sin=y/r
sin=-4/sqrt 41

cos=x/r
cos=-5/sqrt 41

tan=y/x
tan=-4/-5

csc=r/y
csc=sqrt 41/-4

sec=r/x
sec=sqrt 41/-5

cot=x/y
cot=-5/-4

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Jon

  1. they are all correct
    but I would write tanß = 4/5

    also you have no angle after your trig names

    to say sin = 4/5 is a sin. (math joke)

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    Reiny

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