physics

5. A bomber is flying at a height of 9 km at 800 km/h. How far in front of the target should he
drop his bombs? show formulas*

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  1. 800 km/h = 222.2 m/s

    Bomb fall time = sqrt(2H/g) = 42.9 s
    (neglecting air resistance)

    Bomb forward motion during fall time =
    42.9*222.2 = 9533 m = 9.53 km

    That is the "lead distance"

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