A high school wrestling mat must be a square with 38-foot sides and contain 2 circles. Suppose the inner circle has a radius of s feet, and the outer circle's radius is 9 feet longer than the inner circle.
What is an expression for the area of the square outside the circle.
I know that i have to get the area of the square and subtract the area of the outer circle.
Hi Jenny,
I could be wrong, but I just finished an Algebra 1 class, and I don't believe they are asking you to solve. They just want you to write out the equation as you would see it if it were not in a word problem. They just want you to right an expression for the area of the square outside the circle though, not to solve. Word problems can be confusing. Does this help?
does any one know how to do pattern and algebra
To find the expression for the area of the square outside the circle, you need to find the area of the square and subtract the area of the outer circle.
1. Calculate the area of the square:
The area of a square is calculated by multiplying the length of one side by itself. In this case, each side of the square is 38 feet, so the area of the square is (38 ft) × (38 ft) = 1,444 square feet.
2. Calculate the radius of the inner circle:
Given that the radius of the inner circle is s feet, we can use this information to find an expression for its area.
3. Calculate the radius of the outer circle:
The radius of the outer circle is 9 feet longer than the inner circle's radius. So the radius of the outer circle is (s + 9) feet.
4. Calculate the area of the outer circle:
The area of a circle is given by the formula πr^2, where π is approximately equal to 3.14. Since the radius of the outer circle is s + 9 feet, the area of the outer circle is π(s + 9)^2 square feet.
5. Subtract the area of the outer circle from the area of the square:
To find the expression for the area of the square outside the circle, subtract the area of the outer circle from the area of the square:
Area of square outside circle = Area of square - Area of outer circle = 1,444 square feet - π(s + 9)^2 square feet.
Therefore, the expression for the area of the square outside the circle is 1,444 - π(s + 9)^2 square feet.