The revenue in dollars of a company selling its products per month is given as, R(x) = 3000x - 20x^2, while the cost in dollars is given by, C(x) = 600x + 4000. Find and simplify P(x), where P(x) is the profit per month.
lol check your math textbook page 356 question #100.
What textbook? :S
business algebra
... are you from UOIT?
To find the profit per month, we subtract the cost from the revenue.
Given that the revenue is R(x) = 3000x - 20x^2 and the cost is C(x) = 600x + 4000, we can write the profit function P(x) as:
P(x) = R(x) - C(x)
Substituting the given expressions:
P(x) = (3000x - 20x^2) - (600x + 4000)
Simplifying this expression:
P(x) = 3000x - 20x^2 - 600x - 4000
P(x) = -20x^2 + 2400x - 4000
Therefore, the profit function P(x) is -20x^2 + 2400x - 4000.