What volume of 6.0 M sulfuric acid is required for the preparation of 500.0 mL of 0.30 M solution?
Steve answered this for you below.
To determine the volume of 6.0 M sulfuric acid required for the preparation of a 0.30 M solution, you need to use the formula:
(C1)(V1) = (C2)(V2)
Where:
C1 = concentration of the first solution (6.0 M sulfuric acid)
V1 = volume of the first solution
C2 = concentration of the second solution (0.30 M)
V2 = volume of the second solution (500.0 mL)
Rearranging the formula to solve for V1, we have:
V1 = (C2)(V2) / C1
Plugging in the given values:
C1 = 6.0 M
V2 = 500.0 mL = 0.500 L
C2 = 0.30 M
V1 = (0.30 M)(0.500 L) / 6.0 M
= 0.025 L or 25 mL
Therefore, you would need to measure 25 mL of 6.0 M sulfuric acid to prepare 500.0 mL of a 0.30 M solution.