how do you find x in 7-=log(x/10^-12)
I will assume that -= is a typo and should be just =
7 = log(x/10^-12)
7 = logx - log 10^-12
7 = logx - (-12)
7-12= logx
-5 = logx
x = 10^-5
the thing is its / instead of - so I thought that I multiply each side by 10^-12 but im not sure
you cannot multiply by 10^12 because that is inside the log.
suppose you had 2 = √(x/4)
You can't multiply by 4, giving
8 = √x
because that would be trying to slide a value through the "walls" of the function calculation
To find the value of x in the equation 7 = log(x/10^-12), we need to eliminate the logarithm and solve for x. Here's how you can do it step-by-step:
Step 1: Rewrite the equation in exponential form. The logarithmic equation log(b) = c is equivalent to the exponential equation b = 10^c. In this case, we have log(x/10^-12) = 7. Rewriting it in exponential form gives us x/10^-12 = 10^7.
Step 2: Simplify the equation. To simplify, we can multiply both sides of the equation by 10^-12 to get rid of the denominator. This gives us x = 10^7 * 10^-12.
Step 3: Apply the laws of exponents. Remember that when multiplying two numbers with the same base, you can add their exponents. In this case, we have 10^7 * 10^-12, which simplifies to 10^(7 + (-12)), which further simplifies to 10^-5.
Step 4: Final answer. Therefore, x = 10^-5.
Hence, the solution to the equation 7 = log(x/10^-12) is x = 10^-5.