What is the slope of the line that passes through (3/5,-2)(-6,2/9)?
I don't even have a good guess at this one. Thanks.
Are you Tim? I think so because you just asked this same question.
yes it is. can you help me?
slope = (2/9 - (-2))/(-6 - 3/5)
= (20/9) / (-33/5)
= (20/9)(-5/33)
= -100/297
To find the slope of a line passing through two given points, you can use the formula:
slope = (y2 - y1) / (x2 - x1)
In this case, the coordinates of your two points are:
Point 1: (3/5, -2)
Point 2: (-6, 2/9)
Now, substitute these values into the slope formula:
slope = ((2/9) - (-2)) / (-6 - (3/5))
To simplify further, convert the fractions to a common denominator:
slope = ((2/9) - (-2)) / (-30/5 - (3/5))
= ((2/9) + (18/9)) / (-33/5)
Now, add the fractions in the numerator:
slope = (20/9) / (-33/5)
To divide fractions, multiply the first fraction by the reciprocal of the second fraction:
slope = (20/9) * (-5/33)
= -100/297
Therefore, the slope of the line passing through (3/5, -2) and (-6, 2/9) is -100/297.