A 1.31-kg block slides across a rough surface such that it slows down with an acceleration of 1.39 m/s2. What is the coefficient of kinetic friction between the block and the surface?
I think you solve it like this...do you have the answer to verify? I am no genius in physics...
Forces in the x direction = friction = mass x acceleration.
friction forces is found by multiplying the coefficient of friction (u) by the normal force.
so. -u x mass x gravity = mass x -acceleration
mass cancels so u = 1.39 / 9.8.
atta go Brenda !
To find the coefficient of kinetic friction between the block and the surface, we need to use the following formula:
F_friction = μ * N
where F_friction is the force of friction, μ is the coefficient of kinetic friction, and N is the normal force between the block and the surface.
First, let's find the normal force. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, since the block is sliding on a rough surface horizontally, the normal force will be equal to the weight of the block.
The weight (W) can be calculated by multiplying the mass (m) of the block by the acceleration due to gravity (g):
W = m * g
where g is approximately equal to 9.8 m/s^2.
W = 1.31 kg * 9.8 m/s^2
W = 12.838 N
Next, we need to calculate the force of friction (F_friction) using Newton's second law of motion:
F_friction = m * a
where m is the mass of the block and a is the acceleration of the block.
F_friction = 1.31 kg * 1.39 m/s^2
F_friction = 1.8159 N
Now, we can substitute the values of F_friction and N into the formula for the coefficient of kinetic friction:
F_friction = μ * N
1.8159 N = μ * 12.838 N
Dividing both sides of the equation by 12.838 N:
μ = 1.8159 N / 12.838 N
μ ≈ 0.141
Therefore, the coefficient of kinetic friction between the block and the surface is approximately 0.141.