# HELP !!! Algebra 2

15. What is the solution of the linear-quadratic system of equations?
{y = x^2 + 5x - 3}
{y - x = 2}

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1. Try substituting those values, and you will see they do not fit either equation.

looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x-3
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or 1
so, y = -3 or 3
the solutions are thus (-5,-3)(1,3)

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2. first things first...calm down. yes, its extremely hard. but we go simple approach. y-x=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x-3 =x^2+4x-5=0.

We factor to get (x-1)(x+5)=0. Thus, x=1, or -5. PLugging in, we get y=-3,3. Thus, (1,3)(-5,-3) are the solutions

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3. makes no sense

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4. what about the first equation?

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5. Find the solutions of the system of equations braceleftze y = x2 + 3 y = x + 15 .

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6. you guys are life savers thank you

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