rate of change

A missile rises vertically from a point on the ground 75,000 feet from a radar station. If the missile is rising at the rate of 16,500 feet per minute at the instant when it is 38,000 feet high, what is the rate of change(in radians per minute) of the missile's angle of elevation from the radar station at this instant?

TIA

Tan Theta= h/75K

d Tan Theta/dt * dTheta/dt = dh/dt * 1/75K

You know dh/dt (given).The derivative of Tan theta is sec^2 Theta. Which you can solve for given the triangle.

So you know everything, solve for dTheta/dt

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asked by Jen
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