Calculus

The velocity of a particle moving along the x-axis is given by f(t)=6-2t cm/sec. Use a graph of f(t)to find the exact change in position of the particle from time t=0 to t=4 seconds.

1. if v = 6 - 2t is the velocity
then
s = 6t - t^2 + c, where s is the distance and c is a constant

at t=0 , s = 0-0+c
at t=4 , s = 24 - 16 + c

change in position is
24-16+c - (0+c) = 8 cm

posted by Reiny

Similar Questions

1. Calculus

Solve: The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds. Find the particle's velocity at t=1 sec. A) 2/3 m/sec B) 4/3 m/sec C) -1/3 m/sec D) 1/6 m/sec Thank you!
2. physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the
3. physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the
4. calculus

The velocity of a particle moving along the t-axis is given by f(t)=2+.05t cm/sec. Use a graph of y=f(t) to find the exact change in position (distance traveled) for the particle from t=2 to t=8.
5. calculus

a particle moves along the x-axis (units in cm) its initial position at t=0 sec is x(0)=15. the figure shows the graph of the particle's velocity v(t). the numbers are areas of the enclosed regions. in the graph 0 to a is 4 under
6. AP Calculus

The position of a particle moving on the x-axis at time t>0 seconds is: x(t)= e^t - t^1/2. a) Find the average velocity of the particel over the interval [1,3]. b) In what direction and how fast is the particle moving at t= 1