Chemistry

Calculate the molar enthalpy for the following reaction.

HCl(aq) + NH3 (aq) --> NH4Cl (aq).
HCl = 50 ml (2.00M) NH3 = 50 ml (2.05 M)
Delta T = 9.28 degrees Celsius. Ccal = 28.9J/g degrees celcius.

  1. 👍
  2. 👎
  3. 👁
  1. The process is the same as the NaOH +HCl problem we did below. The only difference is Ccal is given and you calculate dH in kJ/mol.

    1. 👍
    2. 👎
  2. I don't know the heat capacity of NH4Cl or the density of it, can you please help me figure those out.

    1. 👍
    2. 👎
  3. I think you are supposed to assume the heat capacity of the NH4Cl solution is the same as that of water which is 4.184 J/g*C.
    I think you are to assume that the density of the NH4Cl solution is the same as that of water or 1.00 g/mL which is the usual quoted value.
    I was surprised that the NaOH/HCl problem used 3.91 for the solution instead of 4.184. Most of these problems assume the solutions to be the same as water and the density to be the same as water.

    1. 👍
    2. 👎
  4. Thankyou Dr. Bob and can you please help me on one more question if this reaction goes to completion what would the final concentration of NH4Cl in the calorimeter. I know how to figure it out if its not in the calorimeter but I am wondering if the calculations are different when its inside a calorimeter.

    1. 👍
    2. 👎
  5. I believe you are over thinking this. mols NH4Cl formed is the same whether we do it in a calorimeter or a bucket. mols mol HCl = M x L = 2.00M x 0.050L = 0100 mol. HCl is the limiting reagent (and it will go to completion) so this reaction produces 0.100 mol NH4Cl.
    How much heat is released.
    q, that letter again, = [mass H2O x specific heat H2O x delta T] + [Ccal x delta T] = 0
    q = [100 x 4.184 x 9.28] + [28.9 x 9.28]= 0
    Calculate q which of course is delta H for the reaction. This is the heat produced by the reaction.
    You want delta H in kJ/mol.
    Take your number which is in joules, convert to kJ, then dH/0.1 = dH in kJ/mol.

    1. 👍
    2. 👎
  6. kik

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    A 10.0-g sample of solid NH4Cl is heated in a 5.00-L container to 900.°C. At equilibrium the pressure of NH3(g) is 1.51 atm. NH4Cl(s) mc011-1.jpg NH3(g) + HCl(g) The equilibrium constant, Kp, for the reaction is:

  2. Chemistry

    The reaction of hydrochloric acid (HCl) with ammonia (NH3) is described by the equation: HCl + NH3 → NH4Cl A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely

  3. AP Chem

    When NH3 gas is introduced at one end of a long tube while HCl gas is introduced simultaneously at the other end, a ring of white ammonium chloride is observed to form in the tube after a few minutes. This ring is closer to the

  4. AP Chem

    Reaction 1: NaOH + HCL --> H20 + NaCl delta H of -100.332 kj/mol Reaction 2: NaOH + NH4Cl --> NH3 + H20 : delta H of 358.639 kj/mol Reaction 3: HCl + NH3 --> NH4Cl : delta H of -51.701 kj/mol Use your answers from question 2 above

  1. Chemistry

    Calculate the enthalpy change (ΔH) for: HCl(aq) + NH3(aq) → NH4Cl(aq) The reaction of 50.0 mL of 1.00 M HCl with 50.0 mL of 1.00 M NH3 causes a temperature rise of 6.4 ˚C in the resulting 100.0 mL of solution. The NH4Cl

  2. Chem help

    Which reaction of ammonia does not involve the non-bonding pair of electrons on the nitrogen atom? A NH3(g) + CH3I(g) → CH3NH 3+ I –(s) B NH3(g) + HCl (g) → NH4Cl (s) C 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g) D 2NH3(aq) +

  3. Chemistry

    Please help me with this-- I don't understand it. Calculate the change of enthalpy for the reaction 2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) from the following reactions: Reaction 1: 2Al (s) + 6HCl (aq) --> 2AlCl3 (aq) + 3H2 (g);Change

  4. chemistry

    Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you a) H2(g)+I2(s)--->2HI(g) b) MnO2(s)+2CO(g)--->Mn(s)+2CO2(g) c) NH4Cl(s)--->NH3(g)+HCl(g) is this correct? a) H2(g)+I2(s)--->2HI(g) From tables: G HI

  1. Chemistry

    HCl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l) NH4Cl(aq) + +NaOH(aq) -> NH3(aq) + NaCl(aq) + H2O(l) NH3(aq) + HCl(aq) -> NH4Cl(aq) Write net ionic equations for the three reactions. Show how the first two reactions are arranged

  2. Chemistry

    Estimate the temperature where Delta G = 0 for the following reaction (Given: Delta H=-176 and Delta S = -284.5 J/K NH3 + HCl --> NH4Cl

  3. Chemistry

    Hi, I posted yesterday with this lab question. "Calculate the molar amounts of NaOH used in the reaction with the HCl solution and with the HC2H3O2. I think I got the answer to that with the help that I received. I had 5 mL of

  4. Chem

    NH4Cl(s) → NH3(g) + HCl(g) ΔH°=176 kJ/mol At 25 °C, this reaction has a ΔG° of 91.1 kJ/mol. What is the ΔS° of this reaction?

You can view more similar questions or ask a new question.