Jennifer's dad built 2 rectangular houses for each of her dogs. The first house had a length of 6 feet and a width of 4 feet. The second house had a length and a width that was 2 feet longer than the first. What was the difference in the perimeter of the two doghouses?
A.20
B.14
C.8
D.28
C?
Right.
Josh rides his dirt bike at the motor cross track every Saturday The track is shaped in the form of 2 equilateral triangles. Each side is 25 yds. If josh rides his bike around the track 3 times how far will he have traveled
A.50
B.450
C.150
D.100
B?
I'm sorry -- but I can't help you with this one. I can't visualize a track shaped in the form of two equilateral triangles.
Okay. Thank you anyway.
Darcie measured an octagon for her class activity and found the perimeter to be 68 in. What was the length of each side of the shape
A.544in
B.8.5in
C.17in
D.5.44in
B?
Right.
To find the difference in the perimeter between the two doghouses, we need to calculate the perimeters of each house and then subtract the smaller perimeter from the larger one.
First, let's calculate the perimeter of the first doghouse:
Perimeter = 2 * (Length + Width)
Perimeter = 2 * (6 feet + 4 feet)
Perimeter = 2 * 10 feet
Perimeter = 20 feet
Now, let's calculate the perimeter of the second doghouse. We know that the length and width are 2 feet longer than the first house:
Length = 6 feet + 2 feet = 8 feet
Width = 4 feet + 2 feet = 6 feet
Perimeter of the second doghouse:
Perimeter = 2 * (Length + Width)
Perimeter = 2 * (8 feet + 6 feet)
Perimeter = 2 * 14 feet
Perimeter = 28 feet
Now, let's find the difference in the perimeters:
Difference = Perimeter of the second doghouse - Perimeter of the first doghouse
Difference = 28 feet - 20 feet
Difference = 8 feet
Therefore, the difference in the perimeter of the two doghouses is 8 feet. So, the correct answer is C.