2y-z
--------- for x=-3, y=13, z=5
x
what's the trouble? Plug and chug:
2(13)-5
---------
-3
= (26-5)/-3 = 21/-3 = -7
I thought that was the answer, but I wasn't sure if I should do the division first because of order of operations?
when you have two expressions forming a fraction, you have to consider each expression separately, then divide at the end. If written on a single line, the fraction would be
(2y-z)/x
and you'd evaluate the expression inside the parentheses first, then do the division.
Besides, if you wanted to divide first, what would you divide? How would you pick the part of the numerator to use?
You could rewrite the expression as
2y/x - z/x
then you could divide each term and do the subtraction at the end, but it would involve more work.
Thank you for the explanation. I thought you maybe did everything on top and then divided the bottom number, but that didn't seem right. Thanks a lot though!! You were great help! :)
To evaluate the expression (2y-z)/x for the given values x=-3, y=13, z=5, you need to substitute these values into the expression and compute the result.
Step 1: Substitute x=-3, y=13, z=5 into the expression:
(2y-z)/x = (2*13-5)/(-3)
Step 2: Simplify the expression:
= (26-5)/(-3)
= 21/(-3)
= -7
Therefore, the value of the expression (2y-z)/x for x=-3, y=13, z=5 is -7.