calculus

a particle is moving counterclockwise around the circular path whose equation is x^2+y^2=100 of the abscissa of the particle is increasing by 72in/sec at a point where x=8 find the rate of changeof the cordinate(y) at this point

1. 👍 0
2. 👎 0
3. 👁 300
1. the rate of ordinate change is dy/dt.

x^2 + y^2 = 100
2x dx/dt + 2y dy/dt = 0

when x=8, y=6, so

2(8)(72) + 2(6) dy/dt = 0
12 dy/dt = -1152
dy/dt = -96 in/s

1. 👍 1
2. 👎 0

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