How do I make 5 ml of a final concentration of 20 ug/ml of reagent A in 10% reagent B/ 1X reagent C?
Note: The stock of reagent A is at 1 mg/ml. Reagent C is purchased as 1X. Use the stock of undiluted Reagent B. How do I go about doing this and what will be my final answer/s? These are the only variables given and I haven't left anything out in the question. Thanks and I look forward to your replies.
To make 5 mL of a final concentration of 20 μg/mL of reagent A in 10% reagent B/ 1X reagent C, follow these steps:
Step 1: Calculate the amount of reagent A needed
To determine the amount of reagent A needed, use the formula:
Amount of reagent A (in mg) = Desired final concentration (in mg/mL) * Volume (in mL)
Amount of reagent A (in mg) = 20 μg/mL * 5 mL = 0.02 mg
Step 2: Determine the volume of stock reagent A needed
To calculate the volume of stock reagent A needed, use the formula:
Volume of stock reagent A (in mL) = Amount of reagent A (in mg) / Concentration of stock reagent A (in mg/mL)
Volume of stock reagent A (in mL) = 0.02 mg / 1 mg/mL = 0.02 mL
Step 3: Calculate the volume of reagent B needed
Since reagent B needs to be added at a 10% concentration, the volume of reagent B is calculated as a 10% solution of the total volume (5 mL).
Volume of reagent B (in mL) = 10% * Total volume (in mL)
Volume of reagent B (in mL) = 10% * 5 mL = 0.5 mL
Step 4: Calculate the volume of reagent C needed
Since reagent C is purchased as 1X concentration, the volume of reagent C needed is calculated as a 1X solution of the total volume (5 mL).
Volume of reagent C (in mL) = 1X * Total volume (in mL)
Volume of reagent C (in mL) = 1X * 5 mL = 5 mL
Step 5: Calculate the final volume
The final volume will be the sum of the volumes of reagents A, B, and C.
Final volume (in mL) = Volume of reagent A (in mL) + Volume of reagent B (in mL) + Volume of reagent C (in mL)
Final volume (in mL) = 0.02 mL + 0.5 mL + 5 mL = 5.52 mL
Therefore, to prepare 5 mL of a final concentration of 20 μg/mL of reagent A in 10% reagent B/ 1X reagent C, you will need to use:
- 0.02 mL of stock reagent A (1 mg/mL)
- 0.5 mL of reagent B (undiluted)
- 5 mL of reagent C (1X)
The final volume will be 5.52 mL.