Physics

A 4.5 g bullet is stopped in a block of wood (m= 5.04 kg). The speed of the bullet-plus-wood combination immediately after the collision is 0.298 m/s. What is the original speed of the bullet? Answer in m/s.

I did it like this and got it wrong:
mv=MV
.298= (.0045kg)(velocity)
66.2 m/s= velocity

What did I do wrong? What do I need to do?

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  1. .0045 kg bullet at speed v
    5.04 kg block at speed 0
    initial momentum = .0045 v
    final momentum = ( 5.04 + .0045)(.298)
    so
    .0045 v = 1.50
    v = 334 m/s

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