Suppose that you have an unlimited supply of copper 2 chloride to react with iron. How many moles if copper would be produced by 34.0 grams of iron with the copper 2 chloride solution
To determine the number of moles of copper produced, you need to start by balancing the chemical equation for the reaction between iron and copper (II) chloride:
Fe + CuCl2 -> FeCl2 + Cu
According to the balanced chemical equation, 1 mole of iron reacts with 1 mole of copper (II) chloride to produce 1 mole of copper.
Next, convert the given mass of iron (Fe) to moles by using the molar mass of iron. The molar mass of iron is approximately 55.85 g/mol.
molar mass of iron (Fe) = 55.85 g/mol
moles of iron (Fe) = mass of iron (Fe) / molar mass of iron (Fe)
= 34.0 g / 55.85 g/mol
Calculate the result:
moles of iron (Fe) = 0.609 mol
Since the reaction is 1:1, the number of moles of copper produced will be the same as the moles of iron consumed. Therefore, 0.609 moles of copper would be produced by reacting 34.0 grams of iron with the copper (II) chloride solution.