# Algebra II

Solve 2x^2=3x+2 by graphing. If excat roots cannot be found, state the consecutive integers between which the roots are located.

I don't have an answer but I made a table and plugged in these values for x respectfully: -1/4, -2/4, -3/4, -1, 0

Thats all I have

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1. somehow it's hard to find the roots manually since

b^2 - 4ac <0

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2. first of all bring all terms to one side
2x^2 - 3x - 2 = 0

now let f(x) = 2x^2 - 3x - 2

did you notice that it factors?

f(x) = (2x+1)(x-2)

so the x-intercepts are -1/2 and 2

which then become the roots of the equation from above.

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