chemistry

if 3.0 moles of nitrogen gas are collected in a 35.0 liter container at 20 C what would be the the pressure exerted on the container in atmospheres

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asked by glenn
  1. PV = nRT

    where P = pressure, V = volume, R is a constant = 8.314 J/mol*K, and T is temperature in degrees Kelvin, n is number of moles

    degrees K = 273 + degrees C

    1 liter = 1000 cm^3 = 1000 cm^3* (1 m / 100 cm)^3 = 1000 * (1/1000000) = 1/1000
    = 0.001 m^3

    35 L = 0.0035 m^3

    P*0.0035 = 3*8.314*293

    Solve for P

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  2. I believe 35.0L is 0.035 m^3; i.e.,
    0.001 x 35.0L = 0.0350 m^3

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  3. .035

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    posted by glenn

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