Find an equation in slope-intercept form passing through the points (-4.7, 16.3) and
(-2.9, 16.3). Hint: first find the slope!
slope = (16.3 - 16.3)/(-2.9 + 4.7)
= 0
ahhh, must be a horizontal line
equation of any horizontal line is y = k, where k is a constant.
looking at your points:
y = 16.3
To find the equation of a line in slope-intercept form (y = mx + b), we first need to find the slope (m). The slope is given by the formula:
m = (y2 - y1) / (x2 - x1)
Where (x1, y1) and (x2, y2) are the coordinates of the two points on the line.
Given the two points (-4.7, 16.3) and (-2.9, 16.3), we can substitute these values into the slope formula:
m = (16.3 - 16.3) / (-2.9 - (-4.7))
= 0 / (-2.9 + 4.7)
= 0 / 1.8
= 0
Since the slope (m) is 0, the line is horizontal. To find the equation of a horizontal line, we can use the y-coordinate of any point on the line. In this case, we can use the y-coordinate of (-4.7, 16.3) or (-2.9, 16.3), as they both have the same y-coordinate.
Therefore, the equation of the line passing through the given points is:
y = 16.3
In slope-intercept form, this equation is:
y = 0x + 16.3
Simplifying further, we get:
y = 16.3