algebra

Hooke's law states that the distance an object is stretched varied directly with the force exerted on the object. Suppose the force exerted by 7-kg mass stretches a certain spring 5 cm. To the nearest 0.1 cm. how far will the spring be stretched by the force of an 11-kg mass?

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asked by Isaiah
  1. 7/5 = x
    (x)(11) = ?

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    posted by Joey

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