# math

Rewrite the expression as an algebraic expresion in x:

tan(sin−1x)=

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1. sorry I meant tan(sin^-1 x)=

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2. sin^-1 x is angle in a right - angled triangle where the opposite side is x and the hypotenuse is 1
let that angle be Ø
so really sin^-1 x ----> sinØ = x/1
so the third side is √(1 - x^2)

then tan(sin^-1 x)
= tan Ø
= x/√(1-x^2)

check:

e.g. let x = .5
then sin^-1 (.5) = π/6
and tan(π/6) = .57735

tan(sin^-1 (.5)) = .5/√(1-.25) = .57735
all looks good.

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