Math Trig

Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (12, 5) lies on its terminal side?
Please explain how!

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  1. I know the answer but I don't understand the process. ! If you could explain the process without the answers?!

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  2. plot the point (12,5) and join it to the origin.
    draw a vertical line from the point to the x-axis
    You now have a right-angled triangle with a base (x) of 12 and a height (y) of 5
    Using Pythagoras, we can find the hypotenuse
    h^2 = 12^2 + 5^2 = 169
    h = 13
    let the base angle be Ø

    You should have learned the following definitions
    sinØ = opposite/hypotenuse = 5/13
    cosØ = adjacent/hypotenus = 12/13
    tanØ = opposite/adjacent = 5/12

    of course ...
    cscØ = 13/5
    secØ = 13/12
    cotØ = 12/5

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