What is the mass (in grams) of 9.81 × 1024 molecules of methanol (CH3OH)?
mol CH3OH = 9.81E24/6.02E23 = ?
grams = mol x mola mass
What is the mass, in grams, of 9.88×1024 molecules of methanol (CH3OH)?
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To find the mass of 9.81 × 10^24 molecules of methanol (CH3OH), you need to use the concept of molar mass.
Molar mass refers to the mass of one mole of a substance and is expressed in grams per mole (g/mol). In order to calculate the molar mass of a compound, you must determine the atomic masses of the elements present and then sum them up.
The molecular formula of methanol (CH3OH) consists of carbon (C), hydrogen (H), and oxygen (O) atoms. You can find the atomic masses of these elements on the periodic table:
- The atomic mass of carbon (C) is approximately 12.01 g/mol.
- The atomic mass of hydrogen (H) is approximately 1.01 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
Now, calculate the molar mass of methanol (CH3OH):
Molar mass of CH3OH = (Number of carbon atoms × Atomic mass of carbon) + (Number of hydrogen atoms × Atomic mass of hydrogen) + (Number of oxygen atoms × Atomic mass of oxygen)
Considering the molecular formula CH3OH:
Molar mass of CH3OH = (1 × 12.01 g/mol) + (4 × 1.01 g/mol) + (1 × 16.00 g/mol)
Molar mass of CH3OH = 32.04 g/mol
The molar mass of methanol (CH3OH) is approximately 32.04 g/mol.
To find the mass of 9.81 × 10^24 molecules of methanol (CH3OH), you can use the following steps:
1. Convert the number of molecules to moles.
Number of moles = Number of molecules / Avogadro's number
Avogadro's number = 6.022 × 10^23 mol^-1
Number of moles = (9.81 × 10^24 molecules) / (6.022 × 10^23 mol^-1)
2. Calculate the mass using the molar mass of methanol:
Mass = Number of moles × Molar mass
Mass = (Number of moles) × (Molar mass)
Plug in the values:
Mass = (9.81 × 10^24 molecules) / (6.022 × 10^23 mol^-1) × (32.04 g/mol)
Now, you can calculate the mass of 9.81 × 10^24 molecules of methanol by multiplying the number of moles by the molar mass of methanol.