lim y->2 (sqrt(y+2)-2)/(y-2)
(L'Hopital's Rule)
lim y->2(sqrt(y+2)-2)/(y-2)=
lim y->2 1/2*sqrt(y+2)=
1/2*sqrt(2+2)=
1/4
lim y->2(sqrt(y+2)-2)/(y-2)=
lim y->2 1/2*sqrt(y+2)=
1/2*sqrt(2+2)=
1/4