# Math ( Pre Calc)

Find all real and imaginary roots of the polynomial equation 3x^4-x^3+4x^2-2x-4=0

1. a little synthetic division shows that

3x^4-x^3+4x^2-2x-4 = (x-1)(x+2)(x-2)(3x+1)

that should help

posted by Steve

(x-1)(3x+2)(x^2+2)

posted by Steve

## Similar Questions

1. ### Precalculus

"Show that x^6 - 7x^3 - 8 = 0 has a quadratic form. Then find the two real roots and the four imaginary roots of this equation." I used synthetic division to get the real roots 2 and -1, but I can't figure out how to get the
2. ### Alg II

I'm working with finding roots of polynomial equations with degrees of 3 or higher. I have the equation r(x)=x^4-6x^3+12x^2=6x-13 I used a graphing calculator to find the real roots of 1,-1 Then I did synthetic using -1, and I
3. ### Alg II

I'm working with finding roots of polynomial equations with degrees of 3 or higher. I have the equation r(x)=x^4-6x^3+12x^2=6x-13 I used a graphing calculator to find the real roots of 1,-1 Then I did synthetic using -1, and I
4. ### Pre-Calc/Trig...

Helpp needed, this is sort of confusing me. Describe the nature of the roots for this equation. 2x^2-x+1=0 A. Two real, rational roots B. Two real, irrational roots C. One real, double root D. Two complex roots
5. ### Algebra II

Which describes the number and type of roots of the equation x^2 -625=0? A. 1 real root, 1 imaginary root B. 2 real roots, 2 imaginary roots C. 2 real roots D. 4 real roots. I have x^2 = 625 x = 25 answer: 2 real roots (25 or -25)
6. ### Math

Which describes the number and type of roots of the equation x^2-625=0? A)1 real root, 1 imaginary root B)2 real roots, 2 imaginary roots C)2 real roots D)4 real roots I went with A sqrt x^2= x (which would be the imaginary) and
7. ### Pre Calc

Write an equation to a polynomial function that has the following properties: Fourth degree equation Lead coefficient is -2 Two negative real roots and one positive real root The positive real root has multiplicity of 2
8. ### Cubic Equations

I have three that I need help with if possible. 1. Solve 2x^3 - 3x^2 = 6x - 9 2. Find all real and imaginary roots of the polynomial equation 3x^4 - x^3 + 4x^2 - 2x - 4=0 3. Find a cubic equation with integral coefficients and
9. ### algebra

if a quadratic equation with real coefficents has a discriminant of 10, then what type of roots does it have? A-2 real, rational roots B-2 real, irrational roots C-1 real, irrational roots D-2 imaginary roots
10. ### mathematics

Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0 A. One real root (a double root) B. Two distinct real roots C. Three real roots D. None (two imaginary roots)

More Similar Questions