A particle moving uniformly along the x axis
is located at 17.9 m at 1.45 s and at 3.9 m at
2.7 s.
Find its displacement during this time in-
terval.
Answer in units of m
What is the average velocity speed during this time interval. Answer in units of m/s
14
To find the displacement of the particle during the given time interval, we need to subtract the initial position from the final position.
The initial position of the particle is given as 17.9 m at 1.45 s.
The final position of the particle is given as 3.9 m at 2.7 s.
Displacement = Final position - Initial position
Displacement = 3.9 m - 17.9 m
Displacement = -14 m
Therefore, the displacement of the particle during this time interval is -14 m.
To find the average velocity speed during this time interval, we need to divide the displacement by the time interval.
Time interval = Final time - Initial time
Time interval = 2.7 s - 1.45 s
Time interval = 1.25 s
Average velocity speed = Displacement / Time interval
Average velocity speed = -14 m / 1.25 s
Average velocity speed = -11.2 m/s
Therefore, the average velocity speed during this time interval is -11.2 m/s.